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The Initial velocity of a vehicle moving alengthy a straight route was 0 meters/second. After 10 secs it got to a velocity of 25 met
satela <25.4K>

given that

initial velocity of vehicle = 0 m/s

after t = 10 s

last velocity of the automobile = 25 m/s

currently for average acceleration we have the right to use   so below the acceleration will certainly be 2.5 m/s^2

3 0
10 months ago

What is the formula for Newton"ssecond law?
Setler <38>

occupychristmas.org:

f=ma

Explanation:

6 0
2 months ago

At time t=0 a automobile has actually a velociry of 16m/s. it slows down via an acceleration given by -0.5t, in m/s² for t in secs. it stops
xz_007 <3.2K>

occupychristmas.org:

The occupychristmas.org is D.8s

Explanation:

We understand, For, t = 0, v = 16 ms⁻¹

t = x, v = 0 ms⁻¹;(the vehicle stops)

Now, Definite integral for equation (i), ; -0.5(fracx^22-0)=-16\" alt="=>-0.5(fracx^22-0)=-16\" align="absmiddle" class="latex-formula"> hope you have actually understood this...

pls mark my occupychristmas.org as the brainliest

8 0
1 month ago

Two tiny spheres via charges of 2.5 nC and the other 5.1 nC are sparated by a distance of 1.1 m. What is the electric potentia
otez555 <7>

occupychristmas.org:

hello

all set to chat in comments
3 0
4 months ago

If the voltage throughout a circuit of consistent resistance is doubled, the power dissipated by that circuit will
densk <106>

occupychristmas.org:

Explanation:

The power dissipated in a circuit is given by where

V is the voltage

R is the resistance

In this trouble, the voltage across the circuit is doubled:

V" = 2V

So the new power dissipated is so, the power dissipated will quadruple.

6 0
1 year ago
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